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5k^2+34k-7=0
a = 5; b = 34; c = -7;
Δ = b2-4ac
Δ = 342-4·5·(-7)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(34)-36}{2*5}=\frac{-70}{10} =-7 $$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(34)+36}{2*5}=\frac{2}{10} =1/5 $
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